(19b-2)-6(3b+4)=-7

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Solution for (19b-2)-6(3b+4)=-7 equation: 



(19b-2)-6(3b+4)=-7

We move all terms to the left:

(19b-2)-6(3b+4)-(-7)=0

We add all the numbers together, and all the variables

(19b-2)-6(3b+4)+7=0

We multiply parentheses

(19b-2)-18b-24+7=0

We get rid of parentheses

19b-18b-2-24+7=0

We add all the numbers together, and all the variables

b-19=0

We move all terms containing b to the left, all other terms to the right

b=19

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