(19b-3)-6(3b+4)=-6

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Solution for (19b-3)-6(3b+4)=-6 equation: 



(19b-3)-6(3b+4)=-6

We move all terms to the left:

(19b-3)-6(3b+4)-(-6)=0

We add all the numbers together, and all the variables

(19b-3)-6(3b+4)+6=0

We multiply parentheses

(19b-3)-18b-24+6=0

We get rid of parentheses

19b-18b-3-24+6=0

We add all the numbers together, and all the variables

b-21=0

We move all terms containing b to the left, all other terms to the right

b=21

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