(19b-4)-6(3b+3)=-5

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Solution for (19b-4)-6(3b+3)=-5 equation: 



(19b-4)-6(3b+3)=-5

We move all terms to the left:

(19b-4)-6(3b+3)-(-5)=0

We add all the numbers together, and all the variables

(19b-4)-6(3b+3)+5=0

We multiply parentheses

(19b-4)-18b-18+5=0

We get rid of parentheses

19b-18b-4-18+5=0

We add all the numbers together, and all the variables

b-17=0

We move all terms containing b to the left, all other terms to the right

b=17

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