(19b-7)-6(3b+1)=-7

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Solution for (19b-7)-6(3b+1)=-7 equation:



(19b-7)-6(3b+1)=-7
We move all terms to the left:
(19b-7)-6(3b+1)-(-7)=0
We add all the numbers together, and all the variables
(19b-7)-6(3b+1)+7=0
We multiply parentheses
(19b-7)-18b-6+7=0
We get rid of parentheses
19b-18b-7-6+7=0
We add all the numbers together, and all the variables
b-6=0
We move all terms containing b to the left, all other terms to the right
b=6

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