(19b-7)-6(3b+1)=7

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Solution for (19b-7)-6(3b+1)=7 equation: 



(19b-7)-6(3b+1)=7

We move all terms to the left:

(19b-7)-6(3b+1)-(7)=0

We multiply parentheses

(19b-7)-18b-6-7=0

We get rid of parentheses

19b-18b-7-6-7=0

We add all the numbers together, and all the variables

b-20=0

We move all terms containing b to the left, all other terms to the right

b=20

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