(19b-8)-6(3b+1)=-6

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Solution for (19b-8)-6(3b+1)=-6 equation:



(19b-8)-6(3b+1)=-6
We move all terms to the left:
(19b-8)-6(3b+1)-(-6)=0
We add all the numbers together, and all the variables
(19b-8)-6(3b+1)+6=0
We multiply parentheses
(19b-8)-18b-6+6=0
We get rid of parentheses
19b-18b-8-6+6=0
We add all the numbers together, and all the variables
b-8=0
We move all terms containing b to the left, all other terms to the right
b=8

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