(19x+10)+(11x+50)=180

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Solution for (19x+10)+(11x+50)=180 equation: 



(19x+10)+(11x+50)=180

We move all terms to the left:

(19x+10)+(11x+50)-(180)=0

We get rid of parentheses

19x+11x+10+50-180=0

We add all the numbers together, and all the variables

30x-120=0

We move all terms containing x to the left, all other terms to the right

30x=120

x=120/30

x=4

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