(19x+28)=(9x+52)

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Solution for (19x+28)=(9x+52) equation: 



(19x+28)=(9x+52)

We move all terms to the left:

(19x+28)-((9x+52))=0

We get rid of parentheses

19x-((9x+52))+28=0



We calculate terms in parentheses: -((9x+52)), so:

(9x+52)

We get rid of parentheses

9x+52

Back to the equation:

-(9x+52)



We get rid of parentheses

19x-9x-52+28=0

We add all the numbers together, and all the variables

10x-24=0

We move all terms containing x to the left, all other terms to the right

10x=24

x=24/10

x=2+2/5

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