(19x+3)+(9x+16)+(6x+15)=x

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Solution for (19x+3)+(9x+16)+(6x+15)=x equation: 



(19x+3)+(9x+16)+(6x+15)=x

We move all terms to the left:

(19x+3)+(9x+16)+(6x+15)-(x)=0

We add all the numbers together, and all the variables

-1x+(19x+3)+(9x+16)+(6x+15)=0

We get rid of parentheses

-1x+19x+9x+6x+3+16+15=0

We add all the numbers together, and all the variables

33x+34=0

We move all terms containing x to the left, all other terms to the right

33x=-34

x=-34/33

x=-1+1/33

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