(19x+3)=(9x+16)+(6x+15)

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Solution for (19x+3)=(9x+16)+(6x+15) equation: 



(19x+3)=(9x+16)+(6x+15)

We move all terms to the left:

(19x+3)-((9x+16)+(6x+15))=0

We get rid of parentheses

19x-((9x+16)+(6x+15))+3=0



We calculate terms in parentheses: -((9x+16)+(6x+15)), so:

(9x+16)+(6x+15)

We get rid of parentheses

9x+6x+16+15

We add all the numbers together, and all the variables

15x+31

Back to the equation:

-(15x+31)



We get rid of parentheses

19x-15x-31+3=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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