(19x+8)+(11x+15)=(14x+32)+(9x+26)

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Solution for (19x+8)+(11x+15)=(14x+32)+(9x+26) equation: 



(19x+8)+(11x+15)=(14x+32)+(9x+26)

We move all terms to the left:

(19x+8)+(11x+15)-((14x+32)+(9x+26))=0

We get rid of parentheses

19x+11x-((14x+32)+(9x+26))+8+15=0



We calculate terms in parentheses: -((14x+32)+(9x+26)), so:

(14x+32)+(9x+26)

We get rid of parentheses

14x+9x+32+26

We add all the numbers together, and all the variables

23x+58

Back to the equation:

-(23x+58)



We add all the numbers together, and all the variables

30x-(23x+58)+23=0

We get rid of parentheses

30x-23x-58+23=0

We add all the numbers together, and all the variables

7x-35=0

We move all terms containing x to the left, all other terms to the right

7x=35

x=35/7

x=5

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