(19x-2)(16x+2)=75

Solution for (19x-2)(16x+2)=75 equation:

(19x-2)(16x+2)=75

We move all terms to the left:

(19x-2)(16x+2)-(75)=0

We multiply parentheses ..

(+304x^2+38x-32x-4)-75=0

We get rid of parentheses

304x^2+38x-32x-4-75=0

We add all the numbers together, and all the variables

304x^2+6x-79=0

a = 304; b = 6; c = -79;
Δ = b2-4ac
Δ = 62-4·304·(-79)
Δ = 96100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{96100}=310$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-310}{2*304}=\frac{-316}{608}
=-79/152
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+310}{2*304}=\frac{304}{608}
=1/2
$