(1=7x+2)=(3=3x+8)

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Solution for (1=7x+2)=(3=3x+8) equation: 



(1=7x+2)=(3=3x+8)

We move all terms to the left:

(1-(7x+2))=0



We calculate terms in parentheses: +(1-(7x+2)), so:

1-(7x+2)

determiningTheFunctionDomain
-(7x+2)+1

We get rid of parentheses

-7x-2+1

We add all the numbers together, and all the variables

-7x-1

Back to the equation:

+(-7x-1)



We get rid of parentheses

-7x-1=0

We move all terms containing x to the left, all other terms to the right

-7x=1

x=1/-7

x=-1/7

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