(1b-3)+b=71

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Solution for (1b-3)+b=71 equation: 



(1b-3)+b=71

We move all terms to the left:

(1b-3)+b-(71)=0

We add all the numbers together, and all the variables

(b-3)+b-71=0

We add all the numbers together, and all the variables

b+(b-3)-71=0

We get rid of parentheses

b+b-3-71=0

We add all the numbers together, and all the variables

2b-74=0

We move all terms containing b to the left, all other terms to the right

2b=74

b=74/2

b=37

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