(1c-1)-(1-1c)=2c-2

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Solution for (1c-1)-(1-1c)=2c-2 equation:


Simplifying
(1c + -1) + -1(1 + -1c) = 2c + -2

Reorder the terms:
(-1 + 1c) + -1(1 + -1c) = 2c + -2

Remove parenthesis around (-1 + 1c)
-1 + 1c + -1(1 + -1c) = 2c + -2
-1 + 1c + (1 * -1 + -1c * -1) = 2c + -2
-1 + 1c + (-1 + 1c) = 2c + -2

Reorder the terms:
-1 + -1 + 1c + 1c = 2c + -2

Combine like terms: -1 + -1 = -2
-2 + 1c + 1c = 2c + -2

Combine like terms: 1c + 1c = 2c
-2 + 2c = 2c + -2

Reorder the terms:
-2 + 2c = -2 + 2c

Add '2' to each side of the equation.
-2 + 2 + 2c = -2 + 2 + 2c

Combine like terms: -2 + 2 = 0
0 + 2c = -2 + 2 + 2c
2c = -2 + 2 + 2c

Combine like terms: -2 + 2 = 0
2c = 0 + 2c
2c = 2c

Add '-2c' to each side of the equation.
2c + -2c = 2c + -2c

Combine like terms: 2c + -2c = 0
0 = 2c + -2c

Combine like terms: 2c + -2c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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