(1i+2i)+(3-2i)=

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Solution for (1i+2i)+(3-2i)= equation:


(1i+2i)+(3-2i)=0

We simplify the equation to the form, which is simple to understand 
(1i+2i)+(3-2i)=0

Simplifying terms in parentheses
(+3i)+(3-2i)=0

Remove unnecessary parentheses
+3i+(3-2i)=0

Remove unnecessary parentheses
+3i+3-2i=0

We move all terms containing i to the left and all other terms to the right. 
+3i-2i=0-3

We simplify left and right side of the equation. 
+1i=-3

We divide both sides of the equation by 1 to get i. 
i=-3

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