(1r+4)+r=36

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Solution for (1r+4)+r=36 equation: 



(1r+4)+r=36

We move all terms to the left:

(1r+4)+r-(36)=0

We add all the numbers together, and all the variables

(r+4)+r-36=0

We add all the numbers together, and all the variables

r+(r+4)-36=0

We get rid of parentheses

r+r+4-36=0

We add all the numbers together, and all the variables

2r-32=0

We move all terms containing r to the left, all other terms to the right

2r=32

r=32/2

r=16

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