(1x)+(2x)+(3x)+45=150

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Solution for (1x)+(2x)+(3x)+45=150 equation: 



(1x)+(2x)+(3x)+45=150

We move all terms to the left:

(1x)+(2x)+(3x)+45-(150)=0

We add all the numbers together, and all the variables

6x-105=0

We move all terms containing x to the left, all other terms to the right

6x=105

x=105/6

x=17+1/2

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