(1x+18)=(3x-28)

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Solution for (1x+18)=(3x-28) equation: 



(1x+18)=(3x-28)

We move all terms to the left:

(1x+18)-((3x-28))=0

We add all the numbers together, and all the variables

(x+18)-((3x-28))=0

We get rid of parentheses

x-((3x-28))+18=0



We calculate terms in parentheses: -((3x-28)), so:

(3x-28)

We get rid of parentheses

3x-28

Back to the equation:

-(3x-28)



We get rid of parentheses

x-3x+28+18=0

We add all the numbers together, and all the variables

-2x+46=0

We move all terms containing x to the left, all other terms to the right

-2x=-46

x=-46/-2

x=+23

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