(1x+7)(8x+2)=0

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Solution for (1x+7)(8x+2)=0 equation:



(1x+7)(8x+2)=0
We add all the numbers together, and all the variables
(x+7)(8x+2)=0
We multiply parentheses ..
(+8x^2+2x+56x+14)=0
We get rid of parentheses
8x^2+2x+56x+14=0
We add all the numbers together, and all the variables
8x^2+58x+14=0
a = 8; b = 58; c = +14;
Δ = b2-4ac
Δ = 582-4·8·14
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-54}{2*8}=\frac{-112}{16} =-7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+54}{2*8}=\frac{-4}{16} =-1/4 $

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