(1x/5x)-40=2x-4

Solution for (1x/5x)-40=2x-4 equation:

(1x/5x)-40=2x-4

We move all terms to the left:

(1x/5x)-40-(2x-4)=0


Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1x/5x)-(2x-4)-40=0

We get rid of parentheses

1x/5x-2x+4-40=0

We multiply all the terms by the denominator


1x-2x*5x+4*5x-40*5x=0

We add all the numbers together, and all the variables

x-2x*5x+4*5x-40*5x=0

Wy multiply elements

-10x^2+x+20x-200x=0

We add all the numbers together, and all the variables

-10x^2-179x=0

a = -10; b = -179; c = 0;
Δ = b2-4ac
Δ = -1792-4·(-10)·0
Δ = 32041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32041}=179$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-179)-179}{2*-10}=\frac{0}{-20}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-179)+179}{2*-10}=\frac{358}{-20}
=-17+9/10
$