(1xy+8)(1xy-8)=

Solution for (1xy+8)(1xy-8)= equation:

Simplifying
(1xy + 8)(1xy + -8) = 0

Reorder the terms:
(8 + 1xy)(1xy + -8) = 0

Reorder the terms:
(8 + 1xy)(-8 + 1xy) = 0

Multiply (8 + 1xy) * (-8 + 1xy)
(8(-8 + 1xy) + 1xy * (-8 + 1xy)) = 0
((-8 * 8 + 1xy * 8) + 1xy * (-8 + 1xy)) = 0
((-64 + 8xy) + 1xy * (-8 + 1xy)) = 0
(-64 + 8xy + (-8 * 1xy + 1xy * 1xy)) = 0
(-64 + 8xy + (-8xy + 1x2y2)) = 0

Combine like terms: 8xy + -8xy = 0
(-64 + 0 + 1x2y2) = 0
(-64 + 1x2y2) = 0

Solving
-64 + 1x2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '64' to each side of the equation.
-64 + 64 + 1x2y2 = 0 + 64

Combine like terms: -64 + 64 = 0
0 + 1x2y2 = 0 + 64
1x2y2 = 0 + 64

Combine like terms: 0 + 64 = 64
1x2y2 = 64

Divide each side by '1y2'.
x2 = 64y-2

Simplifying
x2 = 64y-2

Take the square root of each side:
x = {-8y-1, 8y-1}