(2(3f-1))/3=5-f

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Solution for (2(3f-1))/3=5-f equation:



(2(3f-1))/3=5-f
We move all terms to the left:
(2(3f-1))/3-(5-f)=0
We add all the numbers together, and all the variables
(2(3f-1))/3-(-1f+5)=0
We get rid of parentheses
(2(3f-1))/3+1f-5=0
We multiply all the terms by the denominator
(2(3f-1))+1f*3-5*3=0
We calculate terms in parentheses: +(2(3f-1)), so:
2(3f-1)
We multiply parentheses
6f-2
Back to the equation:
+(6f-2)
We add all the numbers together, and all the variables
(6f-2)+1f*3-15=0
Wy multiply elements
(6f-2)+3f-15=0
We get rid of parentheses
6f+3f-2-15=0
We add all the numbers together, and all the variables
9f-17=0
We move all terms containing f to the left, all other terms to the right
9f=17
f=17/9
f=1+8/9

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