(2(3f-1)/3)=5-f

Solution for (2(3f-1)/3)=5-f equation:

(2(3f-1)/3)=5-f

We move all terms to the left:

(2(3f-1)/3)-(5-f)=0

We add all the numbers together, and all the variables

(2(3f-1)/3)-(-1f+5)=0

We get rid of parentheses

(2(3f-1)/3)+1f-5=0

We multiply all the terms by the denominator


(2(3f-1)+1f*3)-5*3)=0


We calculate terms in parentheses: +(2(3f-1)+1f*3), so:

2(3f-1)+1f*3

We multiply parentheses

6f+1f*3-2

Wy multiply elements

6f+3f-2

We add all the numbers together, and all the variables

9f-2

Back to the equation:

+(9f-2)


We add all the numbers together, and all the variables

(9f-2)=0

We get rid of parentheses

9f-2=0

We move all terms containing f to the left, all other terms to the right

9f=2

f=2/9

f=2/9