(2(4x+10)-70)=10x-40

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Solution for (2(4x+10)-70)=10x-40 equation: 



(2(4x+10)-70)=10x-40

We move all terms to the left:

(2(4x+10)-70)-(10x-40)=0

We get rid of parentheses

(2(4x+10)-70)-10x+40=0



We calculate terms in parentheses: +(2(4x+10)-70), so:

2(4x+10)-70

We multiply parentheses

8x+20-70

We add all the numbers together, and all the variables

8x-50

Back to the equation:

+(8x-50)



We add all the numbers together, and all the variables

-10x+(8x-50)+40=0

We get rid of parentheses

-10x+8x-50+40=0

We add all the numbers together, and all the variables

-2x-10=0

We move all terms containing x to the left, all other terms to the right

-2x=10

x=10/-2

x=-5

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