(2(5x+4))+(60x-3x)+(6x-18)=180

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Solution for (2(5x+4))+(60x-3x)+(6x-18)=180 equation: 



(2(5x+4))+(60x-3x)+(6x-18)=180

We move all terms to the left:

(2(5x+4))+(60x-3x)+(6x-18)-(180)=0

We add all the numbers together, and all the variables

(2(5x+4))+(+57x)+(6x-18)-180=0

We get rid of parentheses

(2(5x+4))+57x+6x-18-180=0



We calculate terms in parentheses: +(2(5x+4)), so:

2(5x+4)

We multiply parentheses

10x+8

Back to the equation:

+(10x+8)



We add all the numbers together, and all the variables

63x+(10x+8)-198=0

We get rid of parentheses

63x+10x+8-198=0

We add all the numbers together, and all the variables

73x-190=0

We move all terms containing x to the left, all other terms to the right

73x=190

x=190/73

x=2+44/73

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