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(2(a+1))/3=2(a-3)
We move all terms to the left:
(2(a+1))/3-(2(a-3))=0
We multiply all the terms by the denominator
(2(a+1))-((2(a-3)))*3=0
We calculate terms in parentheses: +(2(a+1)), so:We get rid of parentheses
2(a+1)
We multiply parentheses
2a+2
Back to the equation:
+(2a+2)
2a-((2(a-3)))*3+2=0
We move all terms containing a to the left, all other terms to the right
2a-((2(a-3)))*3=-2
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