(2(c+3))/3-10=-8

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Solution for (2(c+3))/3-10=-8 equation: 



(2(c+3))/3-10=-8

We move all terms to the left:

(2(c+3))/3-10-(-8)=0

We add all the numbers together, and all the variables

(2(c+3))/3-2=0

We multiply all the terms by the denominator


(2(c+3))-2*3=0



We calculate terms in parentheses: +(2(c+3)), so:

2(c+3)

We multiply parentheses

2c+6

Back to the equation:

+(2c+6)



We add all the numbers together, and all the variables

(2c+6)-6=0

We get rid of parentheses

2c+6-6=0

We add all the numbers together, and all the variables

2c=0

c=0/2

c=0

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