(2(k-3))/4=1

Solution for (2(k-3))/4=1 equation:

(2(k-3))/4=1

We move all terms to the left:

(2(k-3))/4-(1)=0

We multiply all the terms by the denominator


(2(k-3))-1*4=0


We calculate terms in parentheses: +(2(k-3)), so:

2(k-3)

We multiply parentheses

2k-6

Back to the equation:

+(2k-6)


We add all the numbers together, and all the variables

(2k-6)-4=0

We get rid of parentheses

2k-6-4=0

We add all the numbers together, and all the variables

2k-10=0

We move all terms containing k to the left, all other terms to the right

2k=10

k=10/2

k=5