(2(r-5)/7)+3=4

Solution for (2(r-5)/7)+3=4 equation:

(2(r-5)/7)+3=4

We move all terms to the left:

(2(r-5)/7)+3-(4)=0

We add all the numbers together, and all the variables

(2(r-5)/7)-1=0

We multiply all the terms by the denominator


(2(r-5)-1*7)=0


We calculate terms in parentheses: +(2(r-5)-1*7), so:

2(r-5)-1*7

We add all the numbers together, and all the variables

2(r-5)-7

We multiply parentheses

2r-10-7

We add all the numbers together, and all the variables

2r-17

Back to the equation:

+(2r-17)


We get rid of parentheses

2r-17=0

We move all terms containing r to the left, all other terms to the right

2r=17

r=17/2

r=8+1/2