(2(r-5)/7)+3=4

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Solution for (2(r-5)/7)+3=4 equation:



(2(r-5)/7)+3=4
We move all terms to the left:
(2(r-5)/7)+3-(4)=0
We add all the numbers together, and all the variables
(2(r-5)/7)-1=0
We multiply all the terms by the denominator
(2(r-5)-1*7)=0
We calculate terms in parentheses: +(2(r-5)-1*7), so:
2(r-5)-1*7
We add all the numbers together, and all the variables
2(r-5)-7
We multiply parentheses
2r-10-7
We add all the numbers together, and all the variables
2r-17
Back to the equation:
+(2r-17)
We get rid of parentheses
2r-17=0
We move all terms containing r to the left, all other terms to the right
2r=17
r=17/2
r=8+1/2

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