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(2(x+1))/3=4x-6
We move all terms to the left:
(2(x+1))/3-(4x-6)=0
We get rid of parentheses
(2(x+1))/3-4x+6=0
We multiply all the terms by the denominator
(2(x+1))-4x*3+6*3=0
We calculate terms in parentheses: +(2(x+1)), so:We add all the numbers together, and all the variables
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
+(2x+2)
(2x+2)-4x*3+18=0
Wy multiply elements
(2x+2)-12x+18=0
We get rid of parentheses
2x-12x+2+18=0
We add all the numbers together, and all the variables
-10x+20=0
We move all terms containing x to the left, all other terms to the right
-10x=-20
x=-20/-10
x=+2
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