(2(x+1)/3)=3x-4

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Solution for (2(x+1)/3)=3x-4 equation: 



(2(x+1)/3)=3x-4

We move all terms to the left:

(2(x+1)/3)-(3x-4)=0

We get rid of parentheses

(2(x+1)/3)-3x+4=0

We multiply all the terms by the denominator


(2(x+1)-3x*3)+4*3)=0



We calculate terms in parentheses: +(2(x+1)-3x*3), so:

2(x+1)-3x*3

We multiply parentheses

2x-3x*3+2

Wy multiply elements

2x-9x+2

We add all the numbers together, and all the variables

-7x+2

Back to the equation:

+(-7x+2)



We add all the numbers together, and all the variables

(-7x+2)=0

We get rid of parentheses

-7x+2=0

We move all terms containing x to the left, all other terms to the right

-7x=-2

x=-2/-7

x=2/7

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