(2(x+6)/3)=x-5

Solution for (2(x+6)/3)=x-5 equation:

(2(x+6)/3)=x-5

We move all terms to the left:

(2(x+6)/3)-(x-5)=0

We get rid of parentheses

(2(x+6)/3)-x+5=0

We multiply all the terms by the denominator


(2(x+6)-x*3)+5*3)=0


We calculate terms in parentheses: +(2(x+6)-x*3), so:

2(x+6)-x*3

We multiply parentheses

2x-x*3+12

Wy multiply elements

2x-3x+12

We add all the numbers together, and all the variables

-1x+12

Back to the equation:

+(-1x+12)


We add all the numbers together, and all the variables

(-1x+12)=0

We get rid of parentheses

-1x+12=0

We move all terms containing x to the left, all other terms to the right

-x=-12

x=-12/-1

x=+12