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(2(x-1))/3=x+2
We move all terms to the left:
(2(x-1))/3-(x+2)=0
We get rid of parentheses
(2(x-1))/3-x-2=0
We multiply all the terms by the denominator
(2(x-1))-x*3-2*3=0
We calculate terms in parentheses: +(2(x-1)), so:We add all the numbers together, and all the variables
2(x-1)
We multiply parentheses
2x-2
Back to the equation:
+(2x-2)
(2x-2)-x*3-6=0
Wy multiply elements
(2x-2)-3x-6=0
We get rid of parentheses
2x-3x-2-6=0
We add all the numbers together, and all the variables
-1x-8=0
We move all terms containing x to the left, all other terms to the right
-x=8
x=8/-1
x=-8
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