(2(x.x)+4)/(2x+9)=5

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Solution for (2(x.x)+4)/(2x+9)=5 equation: 



(2(x.x)+4)/(2x+9)=5

We move all terms to the left:

(2(x.x)+4)/(2x+9)-(5)=0



Domain of the equation: (2x+9)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-9

x!=-9/2

x!=-4+1/2

x∈R



We add all the numbers together, and all the variables

(2(+x.x)+4)/(2x+9)-5=0

We multiply all the terms by the denominator


(2(+x.x)+4)-5*(2x+9)=0



We calculate terms in parentheses: +(2(+x.x)+4), so:

2(+x.x)+4

We multiply parentheses

2x+4

Back to the equation:

+(2x+4)



We multiply parentheses

(2x+4)-10x-45=0

We get rid of parentheses

2x-10x+4-45=0

We add all the numbers together, and all the variables

-8x-41=0

We move all terms containing x to the left, all other terms to the right

-8x=41

x=41/-8

x=-5+1/8

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