(2(x.x)+4)/(2x+9)=5

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Solution for (2(x.x)+4)/(2x+9)=5 equation:



(2(x.x)+4)/(2x+9)=5
We move all terms to the left:
(2(x.x)+4)/(2x+9)-(5)=0
Domain of the equation: (2x+9)!=0
We move all terms containing x to the left, all other terms to the right
2x!=-9
x!=-9/2
x!=-4+1/2
x∈R
We add all the numbers together, and all the variables
(2(+x.x)+4)/(2x+9)-5=0
We multiply all the terms by the denominator
(2(+x.x)+4)-5*(2x+9)=0
We calculate terms in parentheses: +(2(+x.x)+4), so:
2(+x.x)+4
We multiply parentheses
2x+4
Back to the equation:
+(2x+4)
We multiply parentheses
(2x+4)-10x-45=0
We get rid of parentheses
2x-10x+4-45=0
We add all the numbers together, and all the variables
-8x-41=0
We move all terms containing x to the left, all other terms to the right
-8x=41
x=41/-8
x=-5+1/8

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