(2(z+3))/3=5-z

Solution for (2(z+3))/3=5-z equation:

(2(z+3))/3=5-z

We move all terms to the left:

(2(z+3))/3-(5-z)=0

We add all the numbers together, and all the variables

(2(z+3))/3-(-1z+5)=0

We get rid of parentheses

(2(z+3))/3+1z-5=0

We multiply all the terms by the denominator


(2(z+3))+1z*3-5*3=0


We calculate terms in parentheses: +(2(z+3)), so:

2(z+3)

We multiply parentheses

2z+6

Back to the equation:

+(2z+6)


We add all the numbers together, and all the variables

(2z+6)+1z*3-15=0

Wy multiply elements

(2z+6)+3z-15=0

We get rid of parentheses

2z+3z+6-15=0

We add all the numbers together, and all the variables

5z-9=0

We move all terms containing z to the left, all other terms to the right

5z=9

z=9/5

z=1+4/5