(2)(0.5z2+7)=(z-5)(2)

Solution for (2)(0.5z2+7)=(z-5)(2) equation:

(2)(0.5z^2+7)=(z-5)(2)

We move all terms to the left:

(2)(0.5z^2+7)-((z-5)(2))=0

We multiply parentheses

0z-((z-5)2)+14=0


We calculate terms in parentheses: -((z-5)2), so:

(z-5)2

We multiply parentheses

2z-10

Back to the equation:

-(2z-10)


We add all the numbers together, and all the variables

z-(2z-10)+14=0

We get rid of parentheses

z-2z+10+14=0

We add all the numbers together, and all the variables

-1z+24=0

We move all terms containing z to the left, all other terms to the right

-z=-24

z=-24/-1

z=+24