(2)(2+4)=(3)(3+2x+5)

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Solution for (2)(2+4)=(3)(3+2x+5) equation: 



(2)(2+4)=(3)(3+2x+5)

We move all terms to the left:

(2)(2+4)-((3)(3+2x+5))=0

We add all the numbers together, and all the variables

-(3(2x+8))+26=0



We calculate terms in parentheses: -(3(2x+8)), so:

3(2x+8)

We multiply parentheses

6x+24

Back to the equation:

-(6x+24)



We get rid of parentheses

-6x-24+26=0

We add all the numbers together, and all the variables

-6x+2=0

We move all terms containing x to the left, all other terms to the right

-6x=-2

x=-2/-6

x=1/3

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