(2)(3x+1)=(7)2

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Solution for (2)(3x+1)=(7)2 equation: 



(2)(3x+1)=(7)2

We move all terms to the left:

(2)(3x+1)-((7)2)=0

determiningTheFunctionDomain
2(3x+1)-72=0

We multiply parentheses

6x+2-72=0

We add all the numbers together, and all the variables

6x-70=0

We move all terms containing x to the left, all other terms to the right

6x=70

x=70/6

x=11+2/3

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