(2)(3x-5)(2x-1)=0

Solution for (2)(3x-5)(2x-1)=0 equation:

(2)(3x-5)(2x-1)=0

We multiply parentheses ..

2(+6x^2-3x-10x+5)=0

We multiply parentheses

12x^2-6x-20x+10=0

We add all the numbers together, and all the variables

12x^2-26x+10=0

a = 12; b = -26; c = +10;
Δ = b2-4ac
Δ = -262-4·12·10
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-14}{2*12}=\frac{12}{24}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+14}{2*12}=\frac{40}{24}
=1+2/3
$