(2)(45)=(8y+1)+(5y+10)

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Solution for (2)(45)=(8y+1)+(5y+10) equation: 



(2)(45)=(8y+1)+(5y+10)

We move all terms to the left:

(2)(45)-((8y+1)+(5y+10))=0



We calculate terms in parentheses: -((8y+1)+(5y+10)), so:

(8y+1)+(5y+10)

We get rid of parentheses

8y+5y+1+10

We add all the numbers together, and all the variables

13y+11

Back to the equation:

-(13y+11)



We get rid of parentheses

-13y-11+245=0

We add all the numbers together, and all the variables

-13y+234=0

We move all terms containing y to the left, all other terms to the right

-13y=-234

y=-234/-13

y=+18

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