(2)/((x-4)(x-2))=(1)/(x-4)+(2)/(x-2)

Simple and best practice solution for (2)/((x-4)(x-2))=(1)/(x-4)+(2)/(x-2) equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for (2)/((x-4)(x-2))=(1)/(x-4)+(2)/(x-2) equation: 


D( x )

x-2 = 0

x-4 = 0

(x-4)*(x-2) = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

(x-4)*(x-2) = 0

(x-4)*(x-2) = 0

( x-2 )

x-2 = 0 // + 2

x = 2

( x-4 )

x-4 = 0 // + 4

x = 4

x in (-oo:2) U (2:4) U (4:+oo)

2/((x-4)*(x-2)) = 1/(x-4)+2/(x-2) // - 1/(x-4)+2/(x-2)

2/((x-4)*(x-2))-(1/(x-4))-(2/(x-2)) = 0

2/((x-4)*(x-2))-(x-4)^-1-2*(x-2)^-1 = 0

2/((x-4)*(x-2))-1/(x-4)-2/(x-2) = 0

2/((x-4)*(x-2))+(-1*(x-2))/((x-4)*(x-2))+(-2*(x-4))/((x-4)*(x-2)) = 0

2-1*(x-2)-2*(x-4) = 0

4-x-2*x+8 = 0

12-3*x = 0

(12-3*x)/((x-4)*(x-2)) = 0

(12-3*x)/((x-4)*(x-2)) = 0 // * (x-4)*(x-2)

12-3*x = 0

12-3*x = 0 // - 12

-3*x = -12 // : -3

x = -12/(-3)

x = 4

x in { 4} 

x belongs to the empty set

See similar equations:

| 18-n=-50 | | N*13=-169 | | 0.08(24)+0.02x=0.04(18+x) | | 106=n+(1+n)*2+2 | | 3x+6=2+1(x-1)+3+3 | | 1/2x-9=-2,14 | | X-2/12=8/3 | | .5b+4=(b+2) | | -50-n=18 | | 1/3(y+15)=-13 | | 5(2x-2)-2(4x+1)= | | 5j-6+5.5j=3(5j-2) | | 1+9/5=-1 | | 3+10i^2= | | 6(3x-1)=23 | | (x^2+6x)/(4x+24)=x | | 105=(2x+5) | | y+3=7/9(x+3) | | 7x+6y=4fory | | 14=15-(2x+7) | | f(-7)=-3(-7)+7 | | (-7/8)-(-n)=-7/12 | | 6(2+5k)=36-6k | | 292=n+(1+n)*2+2 | | 175=85+23w | | (2/3)x-9=(5/6)x | | -2r-4=22 | | f(2)=-3(2)+7 | | -6(5x-9)=60 | | 18*-5=3(6*-2) | | 19m+19= | | b+7=-2+b-5+2b |

Equations solver categories