(2)/(3)(6-12y)=-2(4y-4)

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Solution for (2)/(3)(6-12y)=-2(4y-4) equation: 



(2)/(3)(6-12y)=-2(4y-4)

We move all terms to the left:

(2)/(3)(6-12y)-(-2(4y-4))=0



Domain of the equation: 3(6-12y)!=0

y∈R



We add all the numbers together, and all the variables

2/3(-12y+6)-(-2(4y-4))=0

We multiply all the terms by the denominator


-((-2(4y-4)))*3(-12y+6)+2=0



We calculate terms in parentheses: -((-2(4y-4)))*3(-12y+6), so:

(-2(4y-4)))*3(-12y+6

We add all the numbers together, and all the variables

-12y+(-2(4y-4)))*3(+6

Back to the equation:

-(-12y+(-2(4y-4)))*3(+6)



We add all the numbers together, and all the variables

-(-12y+(-2(4y-4)))*36+2=0

We move all terms containing y to the left, all other terms to the right

-(-12y+(-2(4y-4)))*36=-2

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