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(2)/(3)-x+5x=(1)/(2)+x
We move all terms to the left:
(2)/(3)-x+5x-((1)/(2)+x)=0
Domain of the equation: 2+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x)!=-2
x!=-2/1
x!=-2
x∈R
-x+5x-(+x+1/2)+2/3=0
We add all the numbers together, and all the variables
4x-(+x+1/2)+2/3=0
We get rid of parentheses
4x-x-1/2+2/3=0
We calculate fractions
There is no solution for this equation
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