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(2)/(3)=(1)/(3)+3x
We move all terms to the left:
(2)/(3)-((1)/(3)+3x)=0
Domain of the equation: 3+3x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
3x)!=-3
x!=-3/1
x!=-3
x∈R
-(+3x+1/3)+2/3=0
We get rid of parentheses
-3x-1/3+2/3=0
We multiply all the terms by the denominator
-3x*3-1+2=0
We add all the numbers together, and all the variables
-3x*3+1=0
Wy multiply elements
-9x+1=0
We move all terms containing x to the left, all other terms to the right
-9x=-1
x=-1/-9
x=1/9
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