(2)/(3)=(2x+1)/(4)

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Solution for (2)/(3)=(2x+1)/(4) equation: 



(2)/(3)=(2x+1)/(4)

We move all terms to the left:

(2)/(3)-((2x+1)/(4))=0

We calculate fractions


(-((2x+1)*3)/()+()/()=0



We calculate terms in parentheses: +(-((2x+1)*3)/()+()/(), so:

-((2x+1)*3)/()+()/(

We add all the numbers together, and all the variables

-((2x+1)*3)/()+1

We multiply all the terms by the denominator


-((2x+1)*3)+1*()



We calculate terms in parentheses: -((2x+1)*3), so:

(2x+1)*3

We multiply parentheses

6x+3

Back to the equation:

-(6x+3)



We add all the numbers together, and all the variables

-(6x+3)

We get rid of parentheses

-6x-3

Back to the equation:

+(-6x-3)



We get rid of parentheses

-6x-3=0

We move all terms containing x to the left, all other terms to the right

-6x=3

x=3/-6

x=-1/2

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