(2)/(3)a+2=(1)/(3)(4a+1)

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Solution for (2)/(3)a+2=(1)/(3)(4a+1) equation: 



(2)/(3)a+2=(1)/(3)(4a+1)

We move all terms to the left:

(2)/(3)a+2-((1)/(3)(4a+1))=0



Domain of the equation: 3a!=0

a!=0/3

a!=0

a∈R





Domain of the equation: 3(4a+1))!=0

a∈R



We calculate fractions


(6a4/(9a^24+(-(1*3a)/(9a^24+2=0

We do not support eapression: a^24

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