(2)/(3)b-16=-4

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Solution for (2)/(3)b-16=-4 equation: 



(2)/(3)b-16=-4

We move all terms to the left:

(2)/(3)b-16-(-4)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

2/3b-12=0

We multiply all the terms by the denominator


-12*3b+2=0

Wy multiply elements

-36b+2=0

We move all terms containing b to the left, all other terms to the right

-36b=-2

b=-2/-36

b=1/18

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