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(2)/(3)x-(1)/(5)x=(14)/(15)
We move all terms to the left:
(2)/(3)x-(1)/(5)x-((14)/(15))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2/3x-1/5x-(+14/15)=0
We get rid of parentheses
2/3x-1/5x-14/15=0
We calculate fractions
(-1050x^2)/225x^2+150x/225x^2+(-45x)/225x^2=0
We multiply all the terms by the denominator
(-1050x^2)+150x+(-45x)=0
We get rid of parentheses
-1050x^2+150x-45x=0
We add all the numbers together, and all the variables
-1050x^2+105x=0
a = -1050; b = 105; c = 0;
Δ = b2-4ac
Δ = 1052-4·(-1050)·0
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11025}=105$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-105}{2*-1050}=\frac{-210}{-2100} =1/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+105}{2*-1050}=\frac{0}{-2100} =0 $
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