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(2)/(3)y-(2)/(5)=5
We move all terms to the left:
(2)/(3)y-(2)/(5)-(5)=0
Domain of the equation: 3y!=0determiningTheFunctionDomain 2/3y-5-2/5=0
y!=0/3
y!=0
y∈R
We calculate fractions
There is no solution for this equation
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